How do you evaluate #\frac { 7} { 8} + 4\frac { 1} { 2}#?

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Answer 1 · 2017-08-03T17:24:04

#43/8#

#7/8+4 1/2#

Here, #4 1/2# is nothing other than #4+1/2#.

The calculation goes this.....

#7/8+4 1/2#

#=7/8+(4+1/2)#
#=7/8+(4(2)+1)/2#

#=7/8+(8+1)/2#

#=7/8+9/2#

#=7/8+(9(4))/(2(4))#

#=7/8+36/8=(7+36)/8=43/8#

Answer 2 · 2017-08-04T13:37:53

#= 5 3/8#

We can work with the mixed numbers. The values to work with are smaller than if we change to improper fractions.

Add the whole numbers first: then find common denominator

#7/8 + 4 1/2#

#= 4 (?+?)/8#

Make equivalent fractions

#= 4 (7+4)/8" "larr (1/2 = 4/8)#

#= 4 11/8#

#= 4+1 3/8" "larr 11/8 = (8+3)/8#

#= 5 3/8#