How do you evaluate #\frac { 90p q } { 165p }#?

Question

388 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-02T01:27:30

See a solution process below:

First, rewrite the expression as:

#(90/165)(p/p)q#

#p/p = 1# therefore we cannot again rewrite the expression as:

#(90/165)(p/p)q => (90/165) * 1 * q => (90/165)q#

We can next factor the fraction as:

#(90/165)q => ((15 xx 6)/(15 xx 11))q#

Now, cancel common terms to complete the evaluation:

#((color(red)(cancel(color(black)(15))) xx 6)/(color(red)(cancel(color(black)(15))) xx 11))q =>#

#6/11q#

Or

#(6q)/11#