How do you evaluate \frac { 9y } { 10x } \div \frac { 3y } { 2x ^ { 2} y ^ { 5} }?

1 Answer
Nov 19, 2017

(3xy^5)/5

AND

x,y!=0

Explanation:

(9y)/(10x):(3y)/(2x^2y^5)=
={(9y)/(10x)}/{(3y)/(2x^2y^5)}=
=((9y)*(2x^2y^5))/((10x)*(3y))=
=((3)*(1xy^5))/((5)*(1))=
=(3xy^5)/5