How do you evaluate #\frac { \sqrt { - 72} - 2} { 6}#?

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Answer 1 · 2017-08-01T18:21:23

Since we cannot have a square root of a negative number, we have to bring in complex numbers.

#frac{sqrt(-72) - 2}{6}#

# = frac{i sqrt(72) - 2}{6}#

Simplify the square root
# = frac{i sqrt(36*2) - 2}{6}#

# = frac{6i sqrt2 -2 }{6}#

# =( 3isqrt2 - 1 )/3#

# = isqrt2 - 1/3#