How do you evaluate #\frac { x - 3} { x } \cdot \frac { 8x } { 1} #?

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Answer 1 · 2018-01-30T23:03:37

See a solution process below:

First, cancel common terms in the numerator and denominator:

#(x - 3)/color(red)(cancel(color(black)(x))) * (8color(red)(cancel(color(black)(x))))/1 =>#

#(x - 3)8 =>#

#8(x - 3)#

We can now expand the terms in parenthesis by multiplying each term inside the parenthesis by the term outside the parenthesis:

#color(red)(8)(x - 3) =>#

#(color(red)(8) xx x) - (color(red)(8) xx 3) =>#

#8x - 24#

However, going back the original expression we cannot divide by #0# so the answer is:

#8x - 24# Where #x != 0#