Question

How do you evaluate `\frac { x ^ { 3} y } { x ^ { 2} - 3x - 10} \cdot \frac { 5x ^ { 2} - 26x + 5} { x y ^ { 6} }`?

Answer 1

`(x^3-x^2)/(xy^5+2y^5)`

Explanation:

`(x^3y)/(x^2-3x-10)xx(5x^2-26x+5)/(x y^6)`

`(x^3y)/((x +2)(x-5))xx((x-5)(5x-1))/(x y^6)`

`(x^3y)/(x +2)xx(5x-1)/(xy^6)`

`x^2/(x +2)xx(5x-1)/y^5`

`(x^3-x^2)/(xy^5+2y^5)`