How do you evaluate #\frac { x } { 9} - 2> 5#?

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Answer 1 · 2017-11-15T14:03:02

See a solution process below:

FIrst, add #color(red)(2)# to each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#x/9 - 2 + color(red)(2) > 5 + color(red)(2)#

#x/9 - 0 > 7#

#x/9 > 7#

Now, multiply each side of the inequality by #color(red)(9)# to solve for #x# while keeping the inequality balanced:

#color(red)(9) xx x/9 > color(red)(9) xx 7#

#cancel(color(red)(9)) xx x/color(red)(cancel(color(black)(9))) > 63#

#x > 63#