Question

How do you evaluate `\frac{x}{x(x+1)}\times \frac{1}{(x+1)}`?

Answer 1

`1/(x+1)^2`

Explanation:

`"we can simplify the fraction on the left by "color(blue)"cancelling"`
`"the x on the numerator/denominator"`

`rArr(cancel(x)^1)/(cancel(x)^1(x+1))xx1/(x+1)`

`"multiply numerators/denominators together"`

`rArr1/((x+1)(x+1))=1/(x+1)^2`