# How do you evaluate g(-1) given the function g(t)=-5t+1?

Jan 13, 2015

If the function is $g \left(t\right) = - 5 t + 1$ and we're solving for $g \left(- 1\right)$, that simply means we substitute $- 1$ for $t$ into the function:

$g \left(- 1\right) = - 5 \left(- 1\right) + 1$

and then solve:

$g \left(- 1\right) = 5 + 1$
$g \left(- 1\right) = 6$

When simplifying, don't forget that a negative number multiplied by another negative equals a positive number, so $- 5 \cdot \left(- 1\right)$ equals positive $5$.