Question

How do you evaluate `g(x)=lnx` for `x=e^3`?

Answer 1

`=>g(x)=ln(x)=3`

Explanation:

`ln(x)->ln(e^3)" "=" "3ln(e)`

But `ln(e)=1`

`ln(x)->ln(e^3)" "=" "3ln(e)" "=" "3xx1=3`