# How do you evaluate h(-2) given h(x)=3x^2+2-2x?

Mar 19, 2018

See a solution process below:

#### Explanation:

For each occurrence of $\textcolor{red}{x}$ in $h \left(x\right)$ substitute $\textcolor{red}{- 2}$ and evaluate the expression:

$h \left(\textcolor{red}{x}\right) = 3 {\textcolor{red}{x}}^{2} + 2 - 2 \textcolor{red}{x}$ becomes:

$h \left(\textcolor{red}{- 2}\right) = \left(3 \cdot {\left(\textcolor{red}{- 2}\right)}^{2}\right) + 2 - \left(2 \cdot \textcolor{red}{- 2}\right)$

$h \left(\textcolor{red}{- 2}\right) = \left(3 \cdot 4\right) + 2 - \left(- 4\right)$

$h \left(\textcolor{red}{- 2}\right) = 12 + 2 + 4$

$h \left(\textcolor{red}{- 2}\right) = 14 + 4$

$h \left(\textcolor{red}{- 2}\right) = 18$