How do you evaluate \int _ { 2} ^ { x} ( 3t ^ { 2} - 1) d t ?

1 Answer
Oct 26, 2017

x^3 - x - 6

Explanation:

Your antiderivative is going to be t^3 - t

Evaluate that at t = 2:

2^3-2 = 6

Evaluate at t = x:

x^3 - x

...and subtract the lower limit value from the upper:

x^3 - x - 6
GOOD LUCK