How do you evaluate #(j + 6) + ( 3j ^ { 2} + 3j + 1)#?

1 Answer
Jim G.
Feb 1, 2018

#3j^2+4j+7#

Explanation:

#"write the expression without parenthesis and "color(blue)"collect like terms"#

#color(red)(j)color(blue)(+6)color(magenta)(+3j^2)color(red)(+3j)color(blue)(+1)#

#=color(magenta)(3j^2)color(red)(+4j)color(blue)(+7)#

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