How do you evaluate ln (1/e)?

1 Answer
Jun 10, 2016

It is -1.

Explanation:

We apply the properties of the logarithm:

ln(1/e)=ln(e^(-1))

the first property is that the exponent "exit" and multiply the log

ln(e^-1)=-ln(e)

the second property is that the logarithm of the base is 1. The base of the natural logarithm is e then

-ln(e)=-1.

In conclusion

ln(1/e)=-1.