# How do you evaluate ln (1/e)?

Jun 10, 2016

It is $- 1$.

#### Explanation:

We apply the properties of the logarithm:

$\ln \left(\frac{1}{e}\right) = \ln \left({e}^{- 1}\right)$

the first property is that the exponent "exit" and multiply the log

$\ln \left({e}^{-} 1\right) = - \ln \left(e\right)$

the second property is that the logarithm of the base is 1. The base of the natural logarithm is $e$ then

$- \ln \left(e\right) = - 1$.

In conclusion

$\ln \left(\frac{1}{e}\right) = - 1$.