Question

How do you evaluate `ln(1/sqrt e^7)`?

Answer 1

`ln(1/sqrte ^7) = -7/2`

Explanation:

`ln(1/sqrte ^7)`
`=ln 1 - lnsqrte^7`-> use property `log_b(x/y)=log_bx-log_by`
`=0-lne^(7/2)` ->`ln 1=0`
`=-7/2 ln e`->use property `log_b x^n=n*log_bx`
`=-7/2 * 1`->`ln e =1`
`=-7/2`