How do you evaluate ln432=y?
1 Answer
Apr 3, 2017
Explanation:
Suppose you know:
log2≈0.30103
log3≈0.47712
ln10≈2.302585
Then:
ln432ln10=log432=log(2433)=4log2+3log3
So:
ln432=(ln10)(4log2+3log3)
ln432≈2.302585⋅(4⋅0.30103+3⋅0.47712)
ln432≈6.0684