How do you evaluate #ln(ln e^(e^100))#?
2 Answers
Mar 31, 2016
100
Explanation:
The bracketed logarithm
The given expression =
Apr 5, 2016
Explanation:
We have:
#ln(ln(e^(e^100)))#
Within the innermost logarithm, we can use the following rule:
#ln(color(blue)a^color(red)b)=color(red)b*ln(color(blue)a)#
This gives us:
#ln(ln(color(blue)e^(color(red)(e^100))))=ln(color(red)(e^100)*ln(color(blue)(e)))#
Since
#ln(e^100*ln(e))=ln(e^100)#
Using the previously defined exponent rule, we can rewrite this as follows:
#ln(color(blue)e^color(red)100)=color(red)100*ln(color(blue)e)=barul|color(white)(a/a)100color(white)(a/a)|#