# How do you evaluate ln0.03 using a calculator to four decimal places?

$- 3.5066 \left(4 d . p .\right)$
enter $\ln \left(0.03\right)$ or ${\log}_{e} \left(0.03\right)$ into a calculator.
$\ln \left(0.03\right) = {\log}_{e} \left(0.03\right) = - 3.50655 . .$
since the $5$ of the fifth decimal place is rounded up, the value of $\ln \left(0.03\right)$ is $- 3.5066$ to $4$ decimal places $\left(4 d . p .\right)$