How do you evaluate #lne^(-4x)#?

1 Answer
Oct 31, 2016

Answer:

#-4x#

Explanation:

#ln e^(-4x)#=#log_e e^(-4x)#
The way I remember log relationships is
#2^3=8# and #log_2 8=3# are two ways of writing the same thing.
So if #log_e e^(-4x)# = n
Then #e^n=e^(-4x)#
And #n=-4x#

#log_e e^(-4x)= -4x#
Or #ln e^(-4x) =-4x#