Question

How do you evaluate `log_(1/7) (1/343)`?

Answer 1

3

Explanation:

Let `x=log_(1/7) (1/343)`

`:. (1/7)^x =1/343`

Now consider: `1/7 =7^-1` and `1/343 = 1/7^3 = 7^-3`

Hence: `7^-x = 7^-3`

Equating exponents:

`-x =-3 -> x=3`