How do you evaluate # log(1/sqrt1000)#? Precalculus Properties of Logarithmic Functions Common Logs 1 Answer Bdub Mar 22, 2016 #log (1/sqrt1000)=-3/2# Explanation: #log (1/sqrt1000)# #=log(1/sqrt(10^3))# #=log(1/10^(3/2))# #=log10^(-3/2)#->Use property #1/x^n =x^-n# #=-3/2 *log 10#-> Use property #log_bx^n = n* log_bx# #= -3/2 *1# -> log 10 =1 #= -3/2# Answer link Related questions What is the common logarithm of 10? How do I find the common logarithm of a number? What is a common logarithm or common log? What are common mistakes students make with common log? How do I find the common logarithm of 589,000? How do I find the number whose common logarithm is 2.6025? What is the common logarithm of 54.29? What is the value of the common logarithm log 10,000? What is #log_10 10#? How do I work in #log_10# in Excel? See all questions in Common Logs Impact of this question 2852 views around the world You can reuse this answer Creative Commons License