How do you evaluate #(log_(10)x)^2#?

1 Answer
Aug 8, 2018

There's not much to say. If we are given a number, we can solve this. For example, if #x = 100#,
#(log_10(100))^2 = 2^2 = 4#

We know the zero of this function is still #x = 1#. We know that the domain of the function is #x in (0, infty)#. The range is obviously also #[0, infty)#, since it's like #x^2# still.

We could imagine sketching from these properties alone. For low values, this blows up (since log of a number near 0 is a large negative). It is well known that #log# grows far more slowly than #x#, so we expect this to be similar to a log function with a little more life:
graph{log(x)^2 [-1, 20, -1, 2]}