How do you evaluate #log 12 – log 3#?

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Answer 1 · 2018-03-17T08:31:10

#log 4 = 0.602#

If you are subtracting the logs of two numbers, it means that the numbers were being divided,

Change two log terms into one:

#log 12 - log 3#

#= log (12/3)#

#= log 4#

This is as far as you can go without a calculator or tables.

#log 4 = 0.602#