# How do you evaluate #log 1500#?

##### 2 Answers

Sep 9, 2015

#### Explanation:

Well we have

#log1500=log(15*100)=log15+log100#

#=log(3*5)+log10^2#

#=log3+log5+2log10#

#=2log10+log3+log5#

#=2log(2*5)+log3+log5#

#=2log2+log3+3log5#

Sep 10, 2015

If

#### Explanation:

If

# = log100 + log 15#

# = log10^2 + log 15#

# = 2 + log 15#

If you are using tables of logarithms, you'll need scientific notation:

# = 3 + log(1.5)#

# = 3 + 0.1761# (from table)

# = 3.1761#