How do you evaluate ${log}_{169} 13$ $log_169 13$ ?

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Answer 1 · 2016-08-10T11:41:05

$\frac{1}{2}$ $1/2$

Use log_b a=log_c a/log_c#

Here,
${log}_{169} 13$ $log_169 13$

$= \frac{ln 13}{ln 169}$ $=ln 13/ln 169$

$= \frac{ln 13}{{ln 13}^{2}}$ $=ln 13/ln 13^2$

$= \frac{ln 13}{2 ln 13}$ $=ln 13/(2ln 13)$

$= \frac{1}{2}$ $=1/2$ .

How do you evaluate log16913log_169 13?