# How do you evaluate log_2(1/8)?

${\log}_{2} \left(\frac{1}{8}\right) = {\log}_{2} \left(\frac{1}{2} ^ 3\right) = {\log}_{2} {2}^{-} 3 = - 3 {\log}_{2} 2 = - 3$
Use the property ${\log}_{a} {a}^{x} = x$