# How do you evaluate log_3 0.015 using the change of base formula?

Mar 9, 2017

$- 3.823 \text{ to 3 decimal places}$

#### Explanation:

To evaluate ${\log}_{b} x$ by $\textcolor{b l u e}{\text{change of base}}$ use

• (log_c x)/(log_c b) where c is the common base

$\text{Using } {\log}_{10}$ to change the base to.

$\Rightarrow {\log}_{3} 0.015 = \frac{{\log}_{10} 0.015}{{\log}_{10} 3}$

≈-3.823" to 3 decimal places"