How do you evaluate #log_3 0.015# using the change of base formula?
1 Answer
Mar 9, 2017
Explanation:
To evaluate
#log_b x# by#color(blue)"change of base"# use
#• (log_c x)/(log_c b)# where c is the common base
#"Using "log_(10)# to change the base to.
#rArrlog_3 0.015=(log_(10)0.015)/(log_(10)3)#
#≈-3.823" to 3 decimal places"#
