How do you evaluate #log_3 0.015# using the change of base formula?

1 Answer
Mar 9, 2017

Answer:

#-3.823" to 3 decimal places"#

Explanation:

To evaluate #log_b x# by #color(blue)"change of base"# use

#• (log_c x)/(log_c b)# where c is the common base

#"Using "log_(10)# to change the base to.

#rArrlog_3 0.015=(log_(10)0.015)/(log_(10)3)#

#≈-3.823" to 3 decimal places"#