Question

How do you evaluate `log_3 0.015` using the change of base formula?

Answer 1

`-3.823" to 3 decimal places"`

Explanation:

To evaluate `log_b x` by `color(blue)"change of base"` use

`• (log_c x)/(log_c b)` where c is the common base

`"Using "log_(10)` to change the base to.

`rArrlog_3 0.015=(log_(10)0.015)/(log_(10)3)`

`≈-3.823" to 3 decimal places"`