How do you evaluate #log_3 (1/243)#?

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Answer 1 · 2016-10-01T13:46:36

#log_3 (1/243) = log_3 3^-5 = -5#

Logs and exponential equations become much easier to understand if you know the powers up to 1,00.

Note that #243 = 3^5#

#log_3 (1/243)# is asking the question..

#"What index of 3 gives "1/243#?

#1/243 " is which power of " 3#?

#1/243 = 1/3^5 = 3^-5" "larr# here is our answer!

#log_3 (1/243) = log_3 3^-5 = -5#