How do you evaluate $log_3 3root4 [3]$ ?

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Answer 1 · 2016-03-23T18:11:46

I found $5/4$

If I got the idea right I would write it as:
$log_3(3*3^(1/4))=log_3(3^(1+1/4))=log_3(3^(5/4))=5/4$
using the definition of log:
$log_ab=x ->a^x=b$

How do you evaluate log_3 3root4 [3] log_3 3root4 [3] ?