# How do you evaluate #\log _ { 3} x + 2\log _ { 3} x#?

##### 1 Answer

Nov 30, 2017

#### Explanation:

#"simplify using the "color(blue)"laws of logarithms"#

#•color(white)(x)logx+logyhArrlogxy#

#•color(white)(x)logx^nhArrnlogx#

#rArrlog_3x+log_3x^2=log_3x^3#