Question

How do you evaluate `log_343 49`?

Answer 1

`log_343 49=2/3`

Explanation:

`"change the base 243 to base 7"`

`log_343 49=(log_7 49)/(log _7 343)=(log _7 7^2)/(log_7 7^3)=(2*log 7)/(3*log_7 7)`

`log _7 7=1`

`log_343 49=(2*1)/(3*1)`

`log_343 49=2/3`