How do you evaluate log_4 32?

1 Answer
Jul 15, 2015

Use the change of base formula to get:

log_4 32 = (log_2 2^5) / (log_2 2^2) = 5/2

Explanation:

In general, log_a b = (log_c b) / (log_c a)

32 = 2^5 and 4 = 2^2

So log_2(32) = log_2(2^5) = 5

and log_2(4) = log_2(2^2) = 2

Hence log_4(32) = 5/2