Question

How do you evaluate `log_4 4^-0.38`?

Answer 1

I got `-0.38`

Explanation:

We can take the exponent in front of the log and write:

`-0.38log_4(4)=`

but `log_4(4)=1` (from the definition of log) so you get:

`-0.38*1=-0.38`