How do you evaluate #log_5 (132)#?

1 Answer
Nov 21, 2016

Answer:

Please see the explanation.

Explanation:

Use a property of all logarithms:

#log_5(132) = log_10(132)/log_10(5)#

Every calculator has base 10 logarithms but, if you prefer the natural logarithm:

#log_5(132) = ln(132)/ln(5)#

Regardless of which you use, the answer will be the same:

#log_5(132) ~~ 3.03 #