How do you evaluate #log_6 18#?

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Answer 1 · 2016-05-06T20:51:01

Log form and index form are interchangeable.
Value = 1.613

Let #log_6 18 = x# ......................this is in log form

#6^x = 18# ...................................this is in index form.

#6^1 = 6# and #6^2 = 36#, so #x# should be 1.????

#log6^x = log18#

#xlog6 = log18#

#x = log18/log6# ....................there are no laws for this.

Use a calculator to find the value

#x = 1.613#