How do you evaluate $log_6(root5 36)$ ?

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Answer 1 · 2016-04-27T16:59:03

$2/5$

Use $log_a a= 1 and log(a^m)^n=log a^(mn)=mn log a$ .

$log_6root(5) 36=log_6root(5) (6^2)=log_6((root(5)6)^2)=log_6 6^(2/5)=(2/5)log_6 6=2/5$

How do you evaluate log_6(root5 36) log_6(root5 36)?