# How do you evaluate log_8 (1/4)?

I found $- \frac{2}{3}$
We can try to use the change of base formula to change into a log in base $2$ and get:
${\log}_{8} \left(\frac{1}{4}\right) = \frac{{\log}_{2} \left(\frac{1}{4}\right)}{{\log}_{2} \left(8\right)} = \frac{- 2}{3}$