Question

How do you evaluate `log_9 (1/3)`?

Answer 1

`-1/2`

Explanation:

`log_9(1/3) = log_9 3^-1 = -log_9 3`

`= -log_9 9^(1/2)`

`= -1/2`

To check answer

`log_9 (1/3) = ln(1/3)/ln9`

`~= -1.09861/2.19723 ~=-1/2`