How do you evaluate P(-1/2) if #P(x) = 2x^4 + x^3 + 12#?
1 Answer
May 14, 2018
Explanation:
#"to evaluate "P(-1/2)#
#"substitute "x=-1/2" into "P(x)#
#P(color(red)(-1/2))=2(color(red)(-1/2))^4+(color(red)(-1/2))^3+12#
#color(white)(xxxxxx)=(2xx1/16)-1/8+12#
#color(white)(xxxxxx)=cancel(1/8)cancel(-1/8)+12=12#
