How do you evaluate #p/2-5# when p=14?

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Answer 1 · 2016-11-23T19:09:19

2

Begin by substituting #14# in for #p# because that is its value:

#14/2-5#

Follow the order of operations:

P.E.M.D.A.S

Parenthesis, Exponents, Multiply, Divide, Add, Subtract

Skip the first 3 steps (P.E.M.) because that doesn't apply in this problem

So, the first step in this problem is to Divide

*Remember that every fraction is just division

#14/2=7#

So, the problem now looks like:

#7-5#

The next step would be to Add, but that doesn't apply, so subtract

#7-5=2#