How do you evaluate #q-r# if #q=-14# and #r=-6#?

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Answer 1 · 2016-12-06T02:11:21

#-8#

#-14-(-6)#
#-14+6#
#-8#

Answer 2 · 2016-12-06T11:57:19

#- 8#

Where ever there is the letter #q# write -14
Where ever there is the letter #r# write -6

So #q-r# becomes: #-14-(-6)#

Note that #-(-6) -> +6# so we have

#-14+6 = -8#