How do you evaluate #(s-r)/t# given r=-3, s=4, t=-7?

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Answer 1 · 2016-10-26T03:10:17

The answer is #-1#.

Simplify: #(s-r)/t#, where #r=-3#, #s=4#, and #t=-7#

Substitute the values for #r, s#, and #t# into the expression.

#(4-(-3))/(-7)#

Simplify the numerator.

#7/(-7)#

Simplify.

#-7/7=-1#