How do you evaluate sin 360°?

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Answer 1 · 2018-02-18T15:07:57

$0$ $0$

${sin 360}^{\circ}$ $sin 360^@$

$= {sin (180 \cdot 2)}^{\circ}$ $=sin (180*2)^@$

We know that $sin 2 a = 2 sin a cos a$ $sin 2a=2sinacosa$

$=>2 \ sin180^@cos180^@$

but $sin180^@=0,cos180^@=-1$ ,

$<=>2*0*-1$

$=0$

$:.sin 360^@=0$