Question

How do you evaluate `\sqrt { 2x - 1} = \sqrt { x + 8}`?

Answer 1

x=9

Explanation:

`sqrt(2x-1)=sqrt(x+8)`

`"square the both side of equation"`

`(sqrt(2x-1))^2=(sqrt(x+8))^2`

`2x-1=x+8`

`2x-x=8+1`

`x=9`