How do you evaluate #\sqrt { 5} \times \sqrt { 6} \div \sqrt { 30}#?

3 Answers
May 23, 2018

#1#

Explanation:

The key realization here is that we move left to right. We can rewrite #sqrt5*sqrt6# as

#sqrt(5*6)=sqrt30#

Now, we have

#sqrt30/sqrt30#

which obviously simplifies to

#1#

Hope this helps!

May 23, 2018

1

Explanation:

#sqrt5xxsqrt6-:sqrt30=sqrt30-:sqrt30=1#

May 23, 2018

#1#

Explanation:

#"using the "color(blue)"law of radicals"#

#•color(white)(x)sqrtaxxsqrtbhArrsqrt(ab)#

#sqrt5xxsqrt6=sqrt(5xx6)=sqrt30#

#sqrt30-:sqrt30=1#