How do you evaluate #\sqrt { 5} \times \sqrt { 6} \div \sqrt { 30}#?

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Answer 1 · 2018-05-23T19:02:32

#1#

The key realization here is that we move left to right. We can rewrite #sqrt5*sqrt6# as

#sqrt(5*6)=sqrt30#

Now, we have

#sqrt30/sqrt30#

which obviously simplifies to

#1#

Hope this helps!

Answer 2 · 2018-05-23T19:04:21

1

#sqrt5xxsqrt6-:sqrt30=sqrt30-:sqrt30=1#

Answer 3 · 2018-05-23T19:04:30

#1#

#"using the "color(blue)"law of radicals"#

#•color(white)(x)sqrtaxxsqrtbhArrsqrt(ab)#

#sqrt5xxsqrt6=sqrt(5xx6)=sqrt30#

#sqrt30-:sqrt30=1#