How do you evaluate #(\sqrt { 6} + 2) ( \sqrt { 42} - 2) #?

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Answer 1 · 2018-02-20T12:04:58

#sqrt(252)-2sqrt(6)+2sqrt(42)-4#

We have #(sqrt(6)+2)(sqrt(42)-2)#.

We can write this as:

#sqrt(6)(sqrt(42)-2)+2(sqrt(42)-2)#

#sqrt(6)sqrt(42)-2sqrt(6)+2sqrt(42)-4#

#sqrt(252)-2sqrt(6)+2sqrt(42)-4#

Which really is the farthest you can go.

If you want the actual answer, it is:

#19.9#