How do you evaluate #\sqrt { 7n ^ { 9} } \cdot \sqrt { 175n ^ { 11} }#?

1 Answer
AltairSafir
May 3, 2018

#\sqrt(7 n^9)*\sqrt(175 n^11)=35*n^10#

Explanation:

#\sqrt(7 n^9)*\sqrt(175 n^11)=\sqrt(7*175*n^9*n^11)=#
#=\sqrt(7*175)*\sqrt(n^(9+11))=#

#= \sqrt(7*5*5*7) *\sqrt(n^20)=#

#=\sqrt(7^2)*\sqrt(5^2)*n^(20/2)=#

#=7*5*n^10=35*n^10#

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