How do you evaluate #tanx/(4x)# as x approaches 0?
1 Answer
Dec 25, 2016
Please see below.
Explanation:
# = lim_(xrarr0)(1/4 * sinx/x * 1/cosx)#
# = 1/4 * 1 * 1/1 = 1/4#
Please see below.
# = lim_(xrarr0)(1/4 * sinx/x * 1/cosx)#
# = 1/4 * 1 * 1/1 = 1/4#