How do you evaluate the definite integral by the limit definition given #int 3x^2dx# from [1,3]?

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Answer 1 · 2016-11-28T14:15:17

26

#int_1^3(3x^2)dx#

#=[(cancel(3)x^3)/cancel(3)]_1^3#

#[x^3]^3-[x^3]_1#

#=3^3-1^3#

#=27-1=26#