How do you evaluate the definite integral #int 1/x^2 dx# from #[2,3]#?
1 Answer
Sep 25, 2016
Explanation:
Rewrite this as:
#int_2^3x^-2dx#
Use the power rule for integration to tackle this:
#=[x^(-2+1)/(-2+1)]_2^3#
#=[x^-1/(-1)]_2^3#
#=[-1/x]_2^3#
#=-1/3-(-1/2)#
#=1/6#
